Factor completely 16a3b7 + 2a6b4 − 22a4b5
WebQ: Part A: Factor completely 16a3b7 + 2a6b4 − 22a4b5. 2(8a3b7 + a6b4 − 11a4b5) 2a3b4(8b3 + a3 −… 2(8a3b7 + a6b4 − 11a4b5) 2a3b4(8b3 + a3 −… A: Click to see the … WebCorrect answers: 3 question: Under an insurance policy, a maximum of five claims may be filed per year by a policyholder. Let Pn be the probability that a policyholder files n claims during a given year, where n 0,1,2,3,4,5. An actuary makes the following observations: i) Pn≥ 2pn+1 for n= 0, 1,2, 3,4 ii) The difference between pn and pn+1 is the same for n …
Factor completely 16a3b7 + 2a6b4 − 22a4b5
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WebSep 2, 2024 · 2a3b4 (8b3 + a3 − 11ab) Explanation: We have been given with. Factor completely means simplifying the expression at its maximum as much as we can. Taking out the common factors from the given expression we will get. we take the common factor which is of the least power throughtout the expression. like in the given expression we … WebQ: Part A: Factor completely 16a3b7 + 2a6b4 − 22a4b5. 2(8a3b7 + a6b4 − 11a4b5) 2a3b4(8b3 + a3 −… 2(8a3b7 + a6b4 − 11a4b5) 2a3b4(8b3 + a3 −… A: Click to see the answer
WebFeb 14, 2024 · Factor completely 169x2 − 64. (13x + 8)(13x − 8) (13x + 8)2 (13x − 8)2 13x − 8 See answers Advertisement ... Step-by-step explanation: We are given to factor the following expression completely : We will be using he following factorization formula : From (i), we get. Thus, the required factored form of the given expression is . Option ... WebFactor completely. a 4 − 2 a 2 + 1 a^4 - 2a^2 + 1 a 4 ... When factoring polynomials, always factor completely. Do the following. Look for a common factor. Then look at the number of terms. If there are two terms, or binomial, check whether if it can be a difference of squares. If there are three terms, or trinomial, check whether if it can ...
WebOct 6, 2024 · Example 6.5.6. First, identify this expression as a difference of squares. x2 − (2x − 1)2 = (x)2 − (2x − 1)2. Solution: Here use a = x and b = 2x − 1 in the formula for a difference of squares. a2 − b2 = (a + b)(a − b) x2 − (2x − 1)2 = [(x + (2x − 1))][(x − (2x − 1))] = (x + 2x − 1)(x − 2x + 1) = (3x − 1)( − x ...
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