Get property by name c#
WebJul 27, 2010 · Use GetType () method of the type, then look into GetProperties () method and PropertyInfo class. (if you'd like to retrieve the string "propertyName" (for a field called propertyName - use xxx.GetType ().GetFields () [0].Name if it's first field in the class. Share Follow answered Jul 27, 2010 at 8:02 Axarydax 16.3k 20 92 151 Web6 Answers Sorted by: 76 You can use reflection. // Get property array var properties = GetProperties (some_object); foreach (var p in properties) { string name = p.Name; var value = p.GetValue (some_object, null); } private static PropertyInfo [] GetProperties (object obj) { return obj.GetType ().GetProperties (); }
Get property by name c#
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WebOct 16, 2014 · Sorted by: 55. This can be achieved using Expressions: // requires object instance, but you can skip specifying T static string GetPropertyName … WebApr 12, 2024 · C# : How to get current property name via reflection?To Access My Live Chat Page, On Google, Search for "hows tech developer connect"I have a hidden feature ...
WebC# : How to dynamically get a property by name from a C# ExpandoObject?To Access My Live Chat Page, On Google, Search for "hows tech developer connect"As pro... WebThe following code checks whether the first object has any property of the required name: var propertyName = "success"; using var document = JsonDocument.Parse (test); var hasProperty = document.RootElement .EnumerateArray () .Take (1) // Just the first object .Any (o => o.EnumerateObject ().Any (p => p.Name == propertyName));
WebI want to pass in the attribute name and return the value. This will be in a generic util and it will not know the attribute type. Update This is the actual working code if someone needs … WebJan 18, 2024 · You can use Json.NET's own contract resolver for this purpose. Doing so will correctly handle properties with, and without, [JsonProperty(string name)] attributes added, as well as objects with naming strategies or data contract attributes applied directly. First add the following method: public static partial class JsonExtensions { static readonly …
WebGet Property Names using Reflection [C#] To get names of properties for a specific type use method Type.GetProperties. Method returns array of PropertyInfo objects and the …
WebC# : How to get current property name via reflection?To Access My Live Chat Page, On Google, Search for "hows tech developer connect"I have a hidden feature ... credit municipal belfortWebC# : How to dynamically get a property by name from a C# ExpandoObject?To Access My Live Chat Page, On Google, Search for "hows tech developer connect"As pro... credit music videoWebSo, assuming you have a reference to the innermost JObject (containing the View, Product and Offer properties), you can get the name of its containing JProperty like this: JProperty parentProp = (JProperty)jObject.Parent; string name = parentProp.Name; // "Info" Share Improve this answer Follow edited Jun 2, 2014 at 20:41 credit municipal horaireWebFeb 25, 2016 · It looks a little bit scary but don’t worry. Through the type Expression>, you pass the lambda expression for the property. T is the type of the class that holds the property. The next step of the process is to create a utility method to get the name of the property from the lambda expression. buckle down amarillo clencherWebMar 29, 2011 · There are two ways to do this: Models.Test test = new Models.Test (); string DisplayName = test.GetDisplayName (t => t.Name); string DisplayName = Helpers.GetDisplayName (t => t.Name); The first one works by virtue of writing a generic extension method to any TModel (which is all types). This means it will … buckle down animeWebYou can use the C# dynamic type to make things easier. This technique also makes re-factoring simpler as it does not rely on magic-strings. JSON. The JSON string below is a simple response from an HTTP API call, and it defines two properties: Id and Name. {"Id": 1, "Name": "biofractal"} buckle down and rodeoWebFrom C# 6.0 you can use the nameof operator. public CarType MyProperty { get { return (CarType)this [nameof (MyProperty)]}; set { this [nameof (MyProperty)] = value]}; } If you have a method that handles your getter/setter anyway, you can use the C# 4.5 CallerMemberName attribute, in this case you don't even need to repeat the name. buckle down answer key